What Is the Heat of Fusion of a Substance?

The heat of fusion is the energy required to change one gram of a solid into a liquid at its melting point without changing its temperature.

You’ve watched an ice cube melt on a warm countertop and noticed the liquid stays cold even after the last solid chunk disappears. The ice itself never warms above 0°C while any solid remains — every bit of incoming heat goes toward breaking the crystal structure instead of raising the temperature.

That hidden energy transfer is the heat of fusion. It describes exactly how much energy a substance absorbs during melting or releases during freezing. Understanding this concept clears up a lot of confusion about phase changes and shows up constantly in chemistry and physics courses.

What Exactly Is the Heat of Fusion

The heat of fusion — also called the enthalpy of fusion or latent heat of fusion — measures the energy needed to change a substance from solid to liquid at constant pressure. During melting, all the added heat goes into loosening the molecular bonds that hold the solid together.

Temperature stays flat throughout the transition. A pot of ice water stays at 0°C until the last crystal melts, then the liquid can start warming. The same thing happens in reverse: liquid water releases the same energy when it freezes, keeping the temperature at 0°C until solidification finishes.

Common units include joules per gram (J/g), calories per gram (cal/g), and kilojoules per kilogram (kJ/kg). For water, the heat of fusion is approximately 334 J/g or 80 cal/g — one of the highest values among common substances, which is why ice takes a surprisingly long time to melt.

Why the Temperature Stays Constant During Melting

Most people assume that adding heat always raises temperature. Phase changes break that rule, and the confusion is understandable. The energy isn’t lost — it’s doing structural work inside the substance. Here is what happens at the molecular level:

  • Bonds break, not motion: Heat energy goes toward separating molecules from their fixed positions in the crystal lattice rather than increasing their kinetic energy (which would raise temperature).
  • The same energy flows both ways: Melting absorbs heat of fusion; freezing releases the same amount. When water freezes into ice, 334 J of heat is released per gram — that’s why frost can form even when the air temperature is slightly below freezing.
  • Different substances need different amounts: Water’s heat of fusion (334 J/g) is much higher than lead’s (23 J/g). Lead melts quickly because its molecular bonds are easier to break.
  • Latent means “hidden”: The term “latent heat” comes from the Latin word for hidden — the energy is present but not detectable as temperature change.
  • Pressure matters: The heat of fusion is defined at constant pressure because changing pressure can shift the melting point slightly, especially for substances like ice.

Measuring the Heat of Fusion of a Substance

Scientists determine the heat of fusion using calorimetry. A known mass of solid is heated while researchers track the energy input and temperature. The energy required to fully melt the sample without any temperature rise gives the value. A lab document from the University of Illinois measures the expected latent heat of fusion of ice at 333.6 kJ/kg — water phase change data is the reference used in the experiment.

For water, different sources report slightly different numbers due to measurement precision. Some give 333.55 J/g, others round to 334 J/g. The key point is that the value clusters around 334 J/g, and any standard textbook problem uses that approximate figure.

The table below shows the heat of fusion of water expressed in different units and applied to sample masses. All values come from standard reference data.

Unit or Mass Heat Energy Required Source Reference
Per gram 334 J/g ThoughtCo reference
Per kilogram 333.6 kJ/kg Illinois lab document
Per gram (exact) 333.55 J/g Wikipedia enthalpy data
In calories 80 cal/g ThoughtCo example
25 grams of ice 8,350 J (2,000 cal) Melting ice problem
1 kilogram of ice 333.55 kJ Enthalpy of fusion record

How to Calculate the Heat of Fusion

Once you know a substance’s heat of fusion, calculating the energy needed to melt a specific mass is straightforward. The formula is Q = m × L, where Q is heat energy, m is mass, and L is the latent heat of fusion. Here is how to apply it step by step:

  1. Find the substance’s heat of fusion: Look up the value for your material in J/g or kJ/kg. For water, use approximately 334 J/g.
  2. Measure the mass: Determine the mass of solid you need to melt. A typical homework problem might give 50 grams of ice.
  3. Multiply mass by L: Using Q = m × L, plug in the numbers. For 50 g of ice: Q = 50 g × 334 J/g = 16,700 J.
  4. Add any temperature-change energy separately: If you also need to warm the resulting liquid, use Q = m × c × ΔT after the phase change completes.
  5. Check your units: Ensure mass and L use the same unit system (both grams and J/g, or both kilograms and kJ/kg).

The same formula works for freezing. If 50 g of water freezes at 0°C, it releases 16,700 J of heat to the surroundings. That energy must be removed for freezing to occur.

Heat of Fusion Versus Heat of Vaporization

Phase changes between solid and liquid are one type of transition. The liquid-to-gas change involves a separate property called heat of vaporization, and the two are often confused. The difference comes down to the bonds being broken. Melting breaks the relatively weak bonds of a crystal lattice; vaporization breaks the stronger intermolecular forces that hold liquid molecules together.

For water, the heat of vaporization is about 2260 J/g — roughly seven times larger than the heat of fusion. That is why boiling a pot of water takes much more energy than melting the same amount of ice. The same concept Chemistrytalk maps in its heat of fusion article applies to both properties, just at different energy scales.

Here is a quick-reference comparison of the two properties for water:

Property Phase Change Energy Scale
Heat of fusion Solid ↔ Liquid 334 J/g (moderate)
Heat of vaporization Liquid ↔ Gas ~2260 J/g (much larger)
Heat of solidification Liquid ↔ Solid (reverse of fusion) Same value as fusion

The Bottom Line

The heat of fusion is a straightforward but essential concept: the energy needed to melt a solid at its melting point without warming it up. Water’s high value of roughly 334 J/g explains why ice resists melting, why coolers stay cold, and why frost forms slowly. The formula Q = mL lets you calculate the exact energy for any mass of any substance.

If you’re working through phase change problems in your chemistry curriculum, your teacher can help connect the heat of fusion concept to the energy diagrams and calorimetry labs you are covering this term.

References & Sources

  • Illinois. “Latent Heat of Fusion Ice Value” The expected value of the latent heat of fusion of ice is 333.6 kJ/kg.
  • Chemistrytalk. “Heat of Fusion Explained” The heat of fusion (also called enthalpy of fusion or latent heat of fusion) is the quantity of energy needed to melt or freeze a substance under conditions of constant pressure.